Tom Assignment

Technology & Operations Management| Assignment| | apprehension 1: Part (a) result: One E finish product requires: A = 4 (1 x 4) D = 10 (2 x 4 + 2) J = 6(2 x 2 + 1 x 2) L = 2 (1 x 2) Hence: drudgery requirement = A =4, D=10, J=6, L =2 quantities necessitate in order to create E=1, F=2, G=1, H=1. ------------------------------------------------- Part (b) ------------------------------------------------- ------------------------------------------------- trouble No: 2 - Part (a) Solution: 1. E on hand = 12 2. E required for 1 End feature = 2x2+1x2+3x2 = 12 3. E required for 20 End items = 20x12 = 240 4. E required for Additional items = 240 12 = 228 Level| percentage point| Quantity(1)| Quantity(20)| Quantity Held| infallible| 0| sack ITEM| 1| 20| 0| | 1| B| 2| 40| 10| 30| | C| 1| 20| 10| 10| | D| 3| 60| 25| 35| 2| E| 12| 240| 12| 228| | F| 6| great degree Celsius| 30| 90| | G| 2| 40| 5| 35| | H| 12| 240| 0| 240| Problem No: 2 - Part (b) Solution: week =5 to digest the target of End item on start of Week 11.

(1 week end Lt + 3 week end Lt (CRD) + 2 week end Lt (EFGH)) = 6 weeks to complete order ------------------------------------------------- Problem 4: Part (a) Week | 1| 2| 3| 4| 5| 6| 7| 8| 9| 10| 11| 12| 13| 14| degree| | | | | | 80| | | | | | | | | melt Time 2 week Item B(2)| 1| 2| 3| 4| 5| 6| 7| 8| 9| 10| 11| 12| 13| 14| Gross Requirement| | | | clx| | | | | | | | | | | plan Receipt| | | | | | | | | | | | | | | Projected on hand| 60| | | 60 | 20| | | | | | | | | | Net Requirement| |! | | 100| | | | | | | | | | | think vagabond Receipt| | | | 120| | | | | | | | | | | Planned Order Releases| | 120| | | | | | | | | | | | | | | | | | | | | | | | | | | | Lead Time 1 week...If you want to get a good essay, order it on our website: BestEssayCheap.com

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